题目描述
输入两个整数a和b,输出这两个整数的和。a和b都不超过100位。
算法描述
由于a和b都比较大,所以不能直接使用语言中的标准数据类型来存储。对于这种问
题,一般使用数组来处理。
定义一个数组A,A[0]用于存储a的个位,A[1]用于存储a的十位,依此类推。同样可
以用一个数组B来存储b。
计算c = a +
b的时候,首先将A[0]与B[0]相加,如果有进位产生,则把进位(即和的十位数)存入r
,把和的个位数存入C[0],即C[0]等于(A[0]+B[0])%10。然后计算A[1]与B[1]相加,这
时还应将低位进上来的值r也加起来,即C[1]应该是A[1]、B[1]和r三个数的和.如果又
有进位产生,则仍可将新的进位存入到r中,和的个位存到C[1]中。依此类推,即可求出
C的所有位。
最后将C输出即可。
输入格式
输入包括两行,第一行为一个非负整数a,第二行为一个非负整数b。两个整数都不
超过100位,两数的最高位都不是0。
输出格式
输出一行,表示a + b的值。
样例输入
20100122201001221234567890
2010012220100122
样例输出
20100122203011233454668012
代码:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String a = sc.nextLine();
String b = sc.nextLine();
StringBuffer sb1 = new StringBuffer();
StringBuffer sb2 = new StringBuffer();
sb1.append(a);
sb1.reverse();
a = sb1.toString();
sb2.append(b);
sb2.reverse();
b = sb2.toString();
String[] A = a.split("");
String[] B = b.split("");
int r = 0;
if (A.length >= B.length) {
for (int i = 0; i < A.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(A[i]) + r;
A[i] = temp + "";
r = 0;
}
}
if (r != 0)
System.out.print(r);
for (int i = A.length - 1; i >= 0; i--) {
System.out.print(A[i]);
}
} else {
for (int i = 0; i < B.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(B[i]) + r;
B[i] = temp + "";
r = 0;
}
}
for (int i = B.length - 1; i >= 0; i--) {
System.out.print(B[i]);
}
}
}
}
输入格式
输入包括两行,第一行为一个非负整数a,第二行为一个非负整数b。两个整数都不
超过100位,两数的最高位都不是0。
输出格式
输出一行,表示a + b的值。
样例输入
20100122201001221234567890
2010012220100122
样例输出
20100122203011233454668012
代码:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String a = sc.nextLine();
String b = sc.nextLine();
StringBuffer sb1 = new StringBuffer();
StringBuffer sb2 = new StringBuffer();
sb1.append(a);
sb1.reverse();
a = sb1.toString();
sb2.append(b);
sb2.reverse();
b = sb2.toString();
String[] A = a.split("");
String[] B = b.split("");
int r = 0;
if (A.length >= B.length) {
for (int i = 0; i < A.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(A[i]) + r;
A[i] = temp + "";
r = 0;
}
}
if (r != 0)
System.out.print(r);
for (int i = A.length - 1; i >= 0; i--) {
System.out.print(A[i]);
}
} else {
for (int i = 0; i < B.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(B[i]) + r;
B[i] = temp + "";
r = 0;
}
}
for (int i = B.length - 1; i >= 0; i--) {
System.out.print(B[i]);
}
}
}
}
输出格式
输出一行,表示a + b的值。
样例输入
20100122201001221234567890
2010012220100122
样例输出
20100122203011233454668012
代码:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String a = sc.nextLine();
String b = sc.nextLine();
StringBuffer sb1 = new StringBuffer();
StringBuffer sb2 = new StringBuffer();
sb1.append(a);
sb1.reverse();
a = sb1.toString();
sb2.append(b);
sb2.reverse();
b = sb2.toString();
String[] A = a.split("");
String[] B = b.split("");
int r = 0;
if (A.length >= B.length) {
for (int i = 0; i < A.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(A[i]) + r;
A[i] = temp + "";
r = 0;
}
}
if (r != 0)
System.out.print(r);
for (int i = A.length - 1; i >= 0; i--) {
System.out.print(A[i]);
}
} else {
for (int i = 0; i < B.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(B[i]) + r;
B[i] = temp + "";
r = 0;
}
}
for (int i = B.length - 1; i >= 0; i--) {
System.out.print(B[i]);
}
}
}
}
20100122201001221234567890
2010012220100122
样例输出
20100122203011233454668012
代码:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String a = sc.nextLine();
String b = sc.nextLine();
StringBuffer sb1 = new StringBuffer();
StringBuffer sb2 = new StringBuffer();
sb1.append(a);
sb1.reverse();
a = sb1.toString();
sb2.append(b);
sb2.reverse();
b = sb2.toString();
String[] A = a.split("");
String[] B = b.split("");
int r = 0;
if (A.length >= B.length) {
for (int i = 0; i < A.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(A[i]) + r;
A[i] = temp + "";
r = 0;
}
}
if (r != 0)
System.out.print(r);
for (int i = A.length - 1; i >= 0; i--) {
System.out.print(A[i]);
}
} else {
for (int i = 0; i < B.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(B[i]) + r;
B[i] = temp + "";
r = 0;
}
}
for (int i = B.length - 1; i >= 0; i--) {
System.out.print(B[i]);
}
}
}
}
20100122203011233454668012
代码:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String a = sc.nextLine();
String b = sc.nextLine();
StringBuffer sb1 = new StringBuffer();
StringBuffer sb2 = new StringBuffer();
sb1.append(a);
sb1.reverse();
a = sb1.toString();
sb2.append(b);
sb2.reverse();
b = sb2.toString();
String[] A = a.split("");
String[] B = b.split("");
int r = 0;
if (A.length >= B.length) {
for (int i = 0; i < A.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
A[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(A[i]) + r;
A[i] = temp + "";
r = 0;
}
}
if (r != 0)
System.out.print(r);
for (int i = A.length - 1; i >= 0; i--) {
System.out.print(A[i]);
}
} else {
for (int i = 0; i < B.length; i++) {
if (i 9) {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp % 10 + r) + "";
r = temp / 10;
} else {
int temp = Integer.parseInt(A[i]) +
Integer.parseInt(B[i]);
B[i] = (temp+r) + "";
r = 0;
}
} else {
int temp = Integer.parseInt(B[i]) + r;
B[i] = temp + "";
r = 0;
}
}
for (int i = B.length - 1; i >= 0; i--) {
System.out.print(B[i]);
}
}
}
}
来源
蓝桥杯 基础训练